The second way of making medazepam consists of the initial reduction of the carbonyl group by lithium aluminum hydride into 7-chloro-5-phenyl-2,3-dihydro-1H-1,4-benzodi-azepin-2-one (5.1.1)—the first intermediate product in the synthesis of diazepam—which is synthesized by the cyclocondensation of 2-amino-5-chlorobenzophenone with glycine ethyl ester into 7-chloro-2,3-dihydro-5-phenyl-1H-1,4-benzodiazepine (5.1.41), and the subsequent methylation of the secondary amine nitrogen atom of the resulting product by methyliodide, using sodium hydride as a base [41,42].
The third method of making medazepam consists of a new way of making 7-chloro-2,3-dihydro-5-phenyl-1H-1,4-benzodiazepine (5.1.41), which consists in heterocyclization of 1-(2,5-dichlorophenyl)-1-phenylimine with ethylenediamine. The starting 1-(2,5-dichlorophenyl)-1-phenylimine (5.1.42) is synthesized by the reaction of 2,5-dichloroben-zonitrile with phenylmagnesiumbromide .
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